在C++中优化strrchr的使用可以通过以下几种方式实现:
std::string str = "hello world";
size_t pos = str.find_last_of('o');
if (pos != std::string::npos) {
// 找到了字符'o'
std::cout << "Last occurrence of 'o' found at position: " << pos << std::endl;
}
std::string str = "hello world";
size_t pos = str.rfind('o');
if (pos != std::string::npos) {
// 找到了字符'o'
std::cout << "Last occurrence of 'o' found at position: " << pos << std::endl;
}
const char* str = "hello world";
size_t len = strlen(str);
const char* pos = static_cast<const char*>(memrchr(str, 'o', len));
if (pos != nullptr) {
// 找到了字符'o'
std::cout << "Last occurrence of 'o' found at position: " << pos - str << std::endl;
}
通过以上方式,可以更加高效地实现在C++中对字符串的查找操作,避免使用低效的strrchr函数。