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sqlite3 数据操作 查询单个信息

发布时间:2020-07-18 16:52:26 来源:网络 阅读:672 作者:缘起愿落 栏目:开发技术



 打开数据库
    sqlite3 * db = [Database openDB];
    
    sqlite3_stmt * stmt = nil;
    NSString * sqlString = [NSString stringWithFormat:@"select * from Student where id = %d" , aID];
    int result = sqlite3_prepare_v2(db, [sqlString UTF8String], -1, &stmt,NULL);
    Student * student = nil;
    if (result == SQLITE_OK) {
        if (sqlite3_step(stmt) == SQLITE_ROW) {
            int ID = sqlite3_column_int(stmt, 0);


            const unsigned char * name = sqlite3_column_text(stmt, 1);
            
            const unsigned char * gender = sqlite3_column_text(stmt ,2);
            int age = sqlite3_column_int(stmt, 3);
            
            int lenght = sqlite3_column_bytes(stmt, 4);
            
            const void * photo = sqlite3_column_blob(stmt, 4);
            
            NSData * photoData = [NSData dataWithBytes:photo length:lenght];
            
            UIImage * p_w_picpath = [UIImage p_w_picpathWithData:photoData];
            
            student = [[Student alloc]init];
            student.ID = ID;
            student.name = [NSString stringWithUTF8String:(const char *)name];
            student.gender = [NSString stringWithUTF8String:(const char *)gender];
            student.age = age;
            
            student.photo = p_w_picpath;
            
            
        }
    }
    
    sqlite3_finalize(stmt);
    [Database closeDB];

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