小编给大家分享一下python如何实现图像拼接,希望大家阅读完这篇文章之后都有所收获,下面让我们一起去探讨吧!
1.待拼接的图像
2. 基于SIFT特征点和RANSAC方法得到的图像特征点匹配结果
3.图像变换结果
4.代码及注意事项
import cv2 import numpy as np def cv_show(name, image): cv2.imshow(name, image) cv2.waitKey(0) cv2.destroyAllWindows() def detectAndCompute(image): image = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY) sift = cv2.xfeatures2d.SIFT_create() (kps, features) = sift.detectAndCompute(image, None) kps = np.float32([kp.pt for kp in kps]) # 得到的点需要进一步转换才能使用 return (kps, features) def matchKeyPoints(kpsA, kpsB, featuresA, featuresB, ratio = 0.75, reprojThresh = 4.0): # ratio是最近邻匹配的推荐阈值 # reprojThresh是随机取样一致性的推荐阈值 matcher = cv2.BFMatcher() rawMatches = matcher.knnMatch(featuresA, featuresB, 2) matches = [] for m in rawMatches: if len(m) == 2 and m[0].distance < ratio * m[1].distance: matches.append((m[0].queryIdx, m[0].trainIdx)) kpsA = np.float32([kpsA[m[0]] for m in matches]) # 使用np.float32转化列表 kpsB = np.float32([kpsB[m[1]] for m in matches]) (M, status) = cv2.findHomography(kpsA, kpsB, cv2.RANSAC, reprojThresh) return (M, matches, status) # 并不是所有的点都有匹配解,它们的状态存在status中 def stich(imgA, imgB, M): result = cv2.warpPerspective(imgA, M, (imgA.shape[1] + imgB.shape[1], imgA.shape[0])) result[0:imageA.shape[0], 0:imageB.shape[1]] = imageB cv_show('result', result) def drawMatches(imgA, imgB, kpsA, kpsB, matches, status): (hA, wA) = imgA.shape[0:2] (hB, wB) = imgB.shape[0:2] # 注意这里的3通道和uint8类型 drawImg = np.zeros((max(hA, hB), wA + wB, 3), 'uint8') drawImg[0:hB, 0:wB] = imageB drawImg[0:hA, wB:] = imageA for ((queryIdx, trainIdx),s) in zip(matches, status): if s == 1: # 注意将float32 --> int pt1 = (int(kpsB[trainIdx][0]), int(kpsB[trainIdx][1])) pt2 = (int(kpsA[trainIdx][0]) + wB, int(kpsA[trainIdx][1])) cv2.line(drawImg, pt1, pt2, (0, 0, 255)) cv_show("drawImg", drawImg) # 读取图像 imageA = cv2.imread('./right_01.png') cv_show("imageA", imageA) imageB = cv2.imread('./left_01.png') cv_show("imageB", imageB) # 计算SIFT特征点和特征向量 (kpsA, featuresA) = detectAndCompute(imageA) (kpsB, featuresB) = detectAndCompute(imageB) # 基于最近邻和随机取样一致性得到一个单应性矩阵 (M, matches, status) = matchKeyPoints(kpsA, kpsB, featuresA, featuresB) # 绘制匹配结果 drawMatches(imageA, imageB, kpsA, kpsB, matches, status) # 拼接 stich(imageA, imageB, M)
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