使用C语言怎么实现一个电子时钟程序？针对这个问题，这篇文章详细介绍了相对应的分析和解答，希望可以帮助更多想解决这个问题的小伙伴找到更简单易行的方法。
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#include<windows.h>
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <time.h>
typedef struct
{
int x;
int y;
}Point;
time_t now;
struct tm *pt, t1, t2;
int printpoint(Point p)
{
Point p1;
p1.x = p.x + 2; p1.y = p.y + 4;
gotoxy(p1.x, p1.y); printf("%c%c", 2, 2);
gotoxy(p1.x, p1.y + 1); printf("%c%c", 2, 2);
p1.y += 4;
gotoxy(p1.x, p1.y); printf("%c%c", 2, 2);
gotoxy(p1.x, p1.y + 1); printf("%c%c", 2, 2);
return 0;
}
int print0(Point p)
{
int i = 0;
for (; i<13; i++)
{
gotoxy(p.x + 1, p.y + i);
if (i == 0 || i == 12)
printf("%c%c%c%c%c%c", 2, 2, 2, 2, 2, 2);
else
printf("%c%4s%c", 2, " ", 2);
}
return 0;
}
int print1(Point p)
{
int i = 0;
for (; i<13; i++)
{
gotoxy(p.x + 1, p.y + i);
printf("%5s%c", " ", 2);
}
return 0;
}
int print2(Point p)
{
int i = 0;
for (; i<13; i++)
{
gotoxy(p.x + 1, p.y + i);
if (i == 0 || i == 6 || i == 12)
printf("%c%c%c%c%c%c", 2, 2, 2, 2, 2, 2);
else if (i>0 && i<6)
printf("%5s%c", " ", 2);
else
printf("%c", 2);
}
return 0;
}
int print3(Point p)
{
int i = 0;
for (; i<13; i++)
{
gotoxy(p.x + 1, p.y + i);
if (i == 0 || i == 6 || i == 12)
printf("%c%c%c%c%c%c", 2, 2, 2, 2, 2, 2);
else
printf("%5s%c", " ", 2);
}
return 0;
}
int print4(Point p)
{
int i = 0;
for (; i<13; i++)
{
gotoxy(p.x + 1, p.y + i);
if (i<6) printf("%c%4s%c", 2, " ", 2);
else if (i == 6)
printf("%c%c%c%c%c%c", 2, 2, 2, 2, 2, 2);
else printf("%5s%c", " ", 2);
}
return 0;
}
int print5(Point p)
{
int i = 0;
for (; i<13; i++)
{
gotoxy(p.x + 1, p.y + i);
if (i == 0 || i == 6 || i == 12)
printf("%c%c%c%c%c%c", 2, 2, 2, 2, 2, 2);
else if (i>0 && i<6)
printf("%c", 2);
else
printf("%5s%c", " ", 2);
}
return 0;
}
int print6(Point p)
{
int i = 0;
for (; i<13; i++)
{
gotoxy(p.x + 1, p.y + i);
if (i == 0 || i == 6 || i == 12)
printf("%c%c%c%c%c%c", 2, 2, 2, 2, 2, 2);
else if (i>0 && i<6)
printf("%c", 2);
else
printf("%c%4s%c", 2, " ", 2);
}
return 0;
}
int print7(Point p)
{
int i = 0;
for (; i<13; i++)
{
gotoxy(p.x + 1, p.y + i);
if (i == 0) printf("%c%c%c%c%c%c", 2, 2, 2, 2, 2, 2);
else printf("%5s%c", " ", 2);
}
return 0;
}
int print8(Point p)
{
int i = 0;
for (; i<13; i++)
{
gotoxy(p.x + 1, p.y + i);
if (i == 0 || i == 6 || i == 12)
printf("%c%c%c%c%c%c", 2, 2, 2, 2, 2, 2);
else printf("%c%4s%c", 2, " ", 2);
}
return 0;
}
int print9(Point p)
{
int i = 0;
for (; i<13; i++)
{
gotoxy(p.x + 1, p.y + i);
if (i == 0 || i == 6 || i == 12)
printf("%c%c%c%c%c%c", 2, 2, 2, 2, 2, 2);
else if (i>0 && i<6)
printf("%c%4s%c", 2, " ", 2);
else
printf("%5s%c", " ", 2);
}
return 0;
}
int clear(Point p)
{
int i = 0;
for (; i<13; i++)
gotoxy(p.x, p.y + i); printf("%16s", " ");
return 0;
}
int printtime(Point p, int n)
{
int a, b;
Point pp;
a = n / 10, b = n % 10;
pp.x = p.x + 8, pp.y = p.y;
switch (a)
{
case 0: print0(p); break;
case 1: print1(p); break;
case 2: print2(p); break;
case 3: print3(p); break;
case 4: print4(p); break;
case 5: print5(p); break;
}
switch (b)
{
case 0: print0(pp); break;
case 1: print1(pp); break;
case 2: print2(pp); break;
case 3: print3(pp); break;
case 4: print4(pp); break;
case 5: print5(pp); break;
case 6: print6(pp); break;
case 7: print7(pp); break;
case 8: print8(pp); break;
case 9: print9(pp); break;
}
return 0;
}
int main()
{
Point phour, pmin, psec, point1, point2;
phour.x = 9, pmin.x = 32, psec.x = 55;
phour.y = pmin.y = psec.y = 7;
point1.x = 25, point2.x = 49;
point1.y = point2.y = 7;
clrscr();
textbackground(YELLOW); /* 设置背景颜色*/
textcolor(RED); /* 设置数字显示颜色*/
now = time(0);
pt = localtime(&now);
t1 = *pt;
printtime(phour, t1.tm_hour);
printpoint(point1);
printtime(pmin, t1.tm_min);
printpoint(point2);
printtime(psec, t1.tm_sec);
while (1)
{
now = time(0);
pt = localtime(&now);
t2 = *pt;
if (t2.tm_sec != t1.tm_sec)
{
t1 = t2;
clrscr();
printtime(phour, t1.tm_hour);
printpoint(point1);
printtime(pmin, t1.tm_min);
printpoint(point2);
printtime(psec, t1.tm_sec);
}
if (bioskey(1) == 0) continue;
else exit(0);
}
return 0;
}关于使用C语言怎么实现一个电子时钟程序问题的解答就分享到这里了，希望以上内容可以对大家有一定的帮助，如果你还有很多疑惑没有解开，可以关注亿速云行业资讯频道了解更多相关知识。
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