这篇文章给大家介绍怎么在Struts2中利用OGNL表达式对map进行遍历,内容非常详细,感兴趣的小伙伴们可以参考借鉴,希望对大家能有所帮助。
一.Action中的代码:MapAction.java
package com.zx.demo.action; import java.util.ArrayList; import java.util.HashMap; import java.util.List; import java.util.Map; import com.opensymphony.xwork2.ActionSupport; import com.zx.demo.model.Product; import com.zx.demo.model.Student; public class MapAction extends ActionSupport { private Map<String,String> map; private Map<String,Student> studentMap; private Map<String,String[]> arrayMap; private Map<String,List<Student>> listMap; //这里省略get set方法 public String testMap(){ map=new HashMap<String,String>(); map.put("1", "one"); map.put("2", "two"); studentMap=new HashMap<String,Student>(); studentMap.put("student1",new Student(new Long(1),"20034140201","张三1","男",25)); studentMap.put("student2",new Student(new Long(2),"20034140202","张三2","女",26)); studentMap.put("student3",new Student(new Long(3),"20034140202","张三3","男",27)); arrayMap=new HashMap<String,String[]>(); arrayMap.put("arr1", new String[]{"1","2003401","leejie","male","20"}); arrayMap.put("arr2", new String[]{"2","2003402","huanglie","male","25"}); arrayMap.put("arr3", new String[{"3","2003403","lixiaoning","male","21"}); listMap=new HashMap<String,List<Student>>(); List<Student> list1=new ArrayList<Student>(); list1.add(new Student(new Long(1),"20034140201","张三1","男",25)); list1.add(new Student(new Long(2),"20034140202","张三2","男",25)); list1.add(new Student(new Long(3),"20034140203","张三3","男",25)); listMap.put("class1", list1); List<Student> list2=new ArrayList<Student>(); list2.add(new Student(new Long(1),"20034140301","李四1","男",20)); list2.add(new Student(new Long(2),"20034140302","李四2","男",21)); list2.add(new Student(new Long(3),"20034140303","李四3","男",22)); list2.add(new Student(new Long(4),"20034140304","李四4","男",23)); listMap.put("class2", list2); return SUCCESS; } }
二.前端测试页面:testMap.jsp
Java代码
<%@ page contentType="text/html;charset=UTF-8" %> <%@ taglib prefix="s" uri="/struts-tags" %> <html> <head> <title>struts2中的map遍历总结</title> </head> <body> <b>1.map中的key为String,value为String字符串</b><br> <s:iterator value="map" id="column"> <s:property value="#column"/><br> key: <s:property value="key"/><br> value:<s:property value="value"/><br> </s:iterator> ******************************************<br> <table border="1" width="50%" cellspacing="0" cellpadding="0"> <tr> <td>key=value</td> <td>ID</td> <td>num</td> <td>name</td> <td>sex</td> <td>age</td> </tr> ******************************************<br> <b>2.map中的key为String,value为Student对象</b> <s:iterator value="studentMap" id="column"> <tr> <td> <s:property value="#column"/></td> <td> <s:property value="value.id"/></td> <td> <s:property value="value.num"/></td> <td> <s:property value="value.name"/></td> <td> <s:property value="value.sex"/></td> <td> <s:property value="value.age"/></td> </tr> </s:iterator> </table> <p> <table border="1" width="50%" cellspacing="0" cellpadding="0"> <tr> <td>key=value</td> <td>ID</td> <td>num</td> <td>name</td> <td>sex</td> <td>age</td> </tr> ******************************************<br> <b>3.map中的key为String,value为String数组</b> <s:iterator value="arrayMap" id="column"> <tr> <td><s:property value="#column"/></td> <td><s:property value="value[0]"/></td> <td><s:property value="value[1]"/></td> <td><s:property value="value[2]"/></td> <td><s:property value="value[3]"/></td> <td><s:property value="value[4]"/></td> </tr> </s:iterator> </table> <p> <table border="1" width="50%" cellspacing="0" cellpadding="0"> <tr> <td>class</td> <td>ID</td> <td>num</td> <td>name</td> <td>sex</td> <td>age</td> </tr> ******************************************<br> <b>4.map中的key为String,value为list集合</b> <s:iterator value="listMap" id="column"> <s:set name="total" value="#column.value.size"/> <s:iterator value="#column.value" status="s"> <tr> <s:if test="#s.first"> <td rowspan="${total}"> <s:property value="#column.key"/> </td> </s:if> <td> <s:property value="id"/> </td> <td> <s:property value="num"/> </td> <td> <s:property value="name"/> </td> <td><s:property value="sex"/></td> <td><s:property value="age"/></td> </tr> </s:iterator> </s:iterator> </table> </body> </html>
附:map的类型为Map<Integer,List(Menu)>在前端遍历,session.powerList存放的类型是:List(Menu)
<s:iterator value="map" id="mapList"> <s:if test="#mapList.key==0"><!-key为0的是父级菜单-> <s:iterator value="#mapList.value" id="map"> <li class="current"><!--遍历父级菜单,取得其名字--> <b><s:property value="#map.menuName" /></b></a> <ul> <s:iterator value="#session.powerList" id="power"> <!--遍历父级菜单下的所用子菜单--> <s:if test="#power.menuFatherId==#map.menuId"> <li><a onClick="funFrame('admin/<s:property value="#power.menuUrl" />')" ><s:property value="#power.menuName" /></a> </li> </s:if> </s:iterator> </ul> </li> </s:iterator> </s:if> </s:iterator>
关于怎么在Struts2中利用OGNL表达式对map进行遍历就分享到这里了,希望以上内容可以对大家有一定的帮助,可以学到更多知识。如果觉得文章不错,可以把它分享出去让更多的人看到。
免责声明:本站发布的内容(图片、视频和文字)以原创、转载和分享为主,文章观点不代表本网站立场,如果涉及侵权请联系站长邮箱:is@yisu.com进行举报,并提供相关证据,一经查实,将立刻删除涉嫌侵权内容。