这篇文章给大家分享的是有关java复制多向链表的方法的内容。小编觉得挺实用的,因此分享给大家做个参考。一起跟随小编过来看看吧。
多向链表结构如
public class Node{
public int value;
public Node next;
public Node rand;
public Node(int data){
this.value = data;
}
}
方法一:使用HashMap结构
public class CopyFromMultiNode {
public static void main(String[] args){
int[] array = {12,3,4,5,6,77,6,54,56,6,7,87,15,15,15};
//数组转Node
Node head = array2node(array);
Node help = head;
System.out.print("处理前 ");
while(help != null){
System.out.print(help.value + " ");
help = help.next;
}
//使用HashMap结构
Node res = copyFromRand1(head);
System.out.println();
System.out.print("处理后结果:");
while(res != null){
System.out.print(res.value+" ");
res = res.next;
}
}
//使用HashMap结构
public static Node copyFromRand1(Node head){
Node cur = head;
HashMap<Node, Node> map = new HashMap<>();
while(cur != null){
map.put(cur, new Node(cur.value));
cur = cur.next;
}
cur = head;
while(cur != null){
map.get(cur).next = map.get(cur.next);
map.get(cur).rand = map.get(cur.rand);
cur = cur.next;
}
return map.get(head);
}
//数组转Node功能,供测试使用
public static Node array2node(int[] array){
Node head = new Node(array[0]);
Node cur = head;
for(int i=1; i<array.length; i++){
cur.next = new Node(array[i]);
cur = cur.next;
}
return head;
}
//基础node节点结构
public static class Node{
public int value;
public Node next;
public Node rand;
public Node(int data){
this.value = data;
}
}
}
2、使用几个有效变量方法,无需其他结构
//使用几个有效变量方法
//替换方法一的copyFromRand1方法
public static Node copyFromRand2(Node head){
Node next = null;
Node cur = head;
//1 -> 2 -> 3 -> 4 ==> 1 -> 1` -> 2 -> 2` -> 3 -> 3` -> 4 -> 4
//完成链表拼接
while(cur != null){
next = cur.next;
cur.next = new Node(cur.value);
cur.next.next = next;
cur = next;
}
cur = head;
Node curCopy = null;
//添加Node的rand值
while(cur != null){
next = cur.next.next;
curCopy = cur.next.next;
curCopy = cur.rand != null? cur.rand.next: null;
cur = next;
}
Node res = head.next;
cur = head;
//拆分
// 1 -> 1` -> 2 -> 2` -> 3 -> 3` -> 4 -> 4
// ==> 1 -> 2 -> 3 -> 4 和 1`-> 2`-> 3`-> 4`
while(cur != null){
next = cur.next.next;
curCopy = cur.next;
cur.next = next;
curCopy.next = next != null ? next.next:null;
cur = next;
}
return res;
}
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