利用C#如何实现一个窗体抖动功能

发布时间：2020-11-25 14:56:21 阅读：187 作者：Leah 栏目：开发技术

开发者测试专用服务器限时活动，0元免费领，库存有限，领完即止！点击查看>>

今天就跟大家聊聊有关利用C#如何实现一个窗体抖动功能，可能很多人都不太了解，为了让大家更加了解，小编给大家总结了以下内容，希望大家根据这篇文章可以有所收获。

原理：围绕中心点运动一圈

利用C#如何实现一个窗体抖动功能

方法一：通过线程实现

需求:需要using System.Threading;命名空间和button按钮以及for循环

具体代码如下:

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.Threading;//添加线程

namespace Test_Window_jitter
{
  public partial class Form1 : Form
  {
    public Form1()
    {
      InitializeComponent();
    }

    private void Form1_Load(object sender, EventArgs e)
    {
      this.Location = new Point(Screen.PrimaryScreen.WorkingArea.Width/2-this.Width/2,Screen.PrimaryScreen.Bounds.Height/2-this.Height/2);
      button1.BackgroundImage = Image.FromFile("../../img/1.jpg");
      button1.BackgroundImageLayout = ImageLayout.Stretch;
    }

    private void button1_Click(object sender, EventArgs e)
    {
      int x = this.Left;
      int y = this.Top;
      for (int i = 0; i < 3; i++)
      {
        this.Location = new Point(x - 3, y);
        Thread.Sleep(10);//设置执行完上一步停留时间
        this.Location = new Point(x - 3, y - 3);
        Thread.Sleep(10);
        this.Location = new Point(x, y - 3);
        Thread.Sleep(10);
        this.Location = new Point(x + 3, y - 3);
        Thread.Sleep(10);
        this.Location = new Point(x + 3, y);
        Thread.Sleep(10);
        this.Location = new Point(x + 3, y + 3);
        Thread.Sleep(10);
        this.Location = new Point(x, y + 3);
        Thread.Sleep(10);
        this.Location = new Point(x - 3, y + 3);
        Thread.Sleep(10);
        this.Location = new Point(x - 3, y);
        Thread.Sleep(10);
        this.Location = new Point(x, y);
      }
    }
  }
}

方法二：通过计时器实现

需求:timer控件,button按钮,for循环

具体代码如下:

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;

namespace Test_Window_jitter
{
  public partial class Form2 : Form
  {
    public Form2()
    {
      InitializeComponent();
    }

    private void Form2_Load(object sender, EventArgs e)
    {
      this.Location = new Point(Screen.PrimaryScreen.WorkingArea.Width / 2 - this.Width / 2, Screen.PrimaryScreen.Bounds.Height / 2 - this.Height / 2);
    }

    private void button1_Click(object sender, EventArgs e)
    {
      timer1.Start();
    }

    private void timer1_Tick(object sender, EventArgs e)
    {
      int x = this.Left;
      int y = this.Top;
      for (int i = 0; i < 10; i++)
      {
        this.Location = new Point(x - 10, y);
        this.Location = new Point(x - 10, y - 10);
        this.Location = new Point(x, y - 10);
        this.Location = new Point(x + 10, y - 10);
        this.Location = new Point(x + 10, y);
        this.Location = new Point(x + 10, y + 10);
        this.Location = new Point(x, y + 10);
        this.Location = new Point(x - 10, y + 10);
        this.Location = new Point(x - 10, y);
        this.Location = new Point(x, y);
      }
      timer1.Stop();
    }
  }
}

看完上述内容，你们对利用C#如何实现一个窗体抖动功能有进一步的了解吗？如果还想了解更多知识或者相关内容，请关注亿速云行业资讯频道，感谢大家的支持。

亿速云「云服务器」，即开即用、新一代英特尔至强铂金CPU、三副本存储NVMe SSD云盘，价格低至29元/月。点击查看>>

向AI问一下细节

利用C#如何实现一个窗体抖动功能

猜你喜欢

最新资讯

相关推荐

开发者交流群：

相关标签