如何在PHP中实现数据对象映射模式?很多新手对此不是很清楚,为了帮助大家解决这个难题,下面小编将为大家详细讲解,有这方面需求的人可以来学习下,希望你能有所收获。
数据库 test ,user 表结构:
CREATE TABLE `user` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(32) CHARACTER SET utf8 DEFAULT NULL, `mobile` varchar(11) CHARACTER SET utf8 DEFAULT NULL, `regtime` timestamp NULL DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=latin1;
Common\User.php:
<?php namespace Common; class User{ public $id; public $name; public $mobile; public $regtime; protected $db; //构造方法 function __construct($id) { $this->db = new Database\MySQLi(); $conn = $this->db->connect('127.0.0.1', 'root', '', 'test'); $res = $this->db->query("select * from user where id = {$id} limit 1"); $data = $res->fetch_assoc(); $this->id = $data['id']; $this->name = $data['name']; $this->mobile = $data['mobile']; $this->regtime = $data['regtime']; } //析构方法 function __destruct() { $this->db->query("update user set name = '{$this->name}', mobile = '{$this->mobile}', regtime = '{$this->regtime}' where id = {$this->id} limit 1"); } }
Common\Databases\MySQLi.php
<?php namespace Common\Database; use Common\IDatabase; class MySQLi implements IDatabase{ protected $conn; function connect($host, $user, $passwd, $dbname){ $conn = mysqli_connect($host, $user, $passwd ,$dbname); $this->conn = $conn; } function query($sql){ $res = mysqli_query($this->conn, $sql); return $res; } function close(){ mysqli_close($this->conn); } }
入口文件 index.php
<?php define('BASEDIR',__DIR__); //定义根目录常量 include BASEDIR.'/Common/Loader.php'; spl_autoload_register('\\Common\\Loader::autoload'); echo '<meta http-equiv="content-type" content="text/html;charset=utf8">'; /* * 对对象属性的操作就完成了对数据库的操作 */ $user = new Common\User(1); //读取数据 var_dump($user->id, $user->mobile, $user->name, $user->regtime);exit(); $user->mobile = '13800138000'; $user->name = 'Arshavin'; $user->regtime = date("Y-m-d H:i:s",time());
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