这篇“如何用C语言递归实现线索二叉树”文章的知识点大部分人都不太理解,所以小编给大家总结了以下内容,内容详细,步骤清晰,具有一定的借鉴价值,希望大家阅读完这篇文章能有所收获,下面我们一起来看看这篇“如何用C语言递归实现线索二叉树”文章吧。
描述:将二叉树中结点的空左孩子指针域指向前驱结点,将空的右孩子指针域指向后继结点。
code:
#pragma warning(disable:4996) #include<stdio.h> #include<stdlib.h> typedef struct TreeNode { char data; struct TreeNode *lchild, *rchild; int ltag, rtag; }Tree,*BTree; BTree Build_Tree(void) { BTree T; char ch; scanf("%c", &ch); if (ch == '#') { T = NULL; } else { T = (BTree)malloc(sizeof(Tree)); T->data = ch; T->ltag = 0; T->rtag = 0; T->lchild = Build_Tree(); T->rchild = Build_Tree(); } return T; } //先序线索化 void Pre_Thread(BTree cur, BTree *pre) { if (cur && cur->ltag==0) { printf("%c ", cur->data); if (cur->lchild == NULL) { cur->lchild = *pre; (*pre)->ltag = 1; cur->ltag = 1; } if (cur->rchild == NULL) { cur->rtag = 1; } if (*pre && (*pre)->rtag == 1) { (*pre)->rchild = cur; } *pre = cur; Pre_Thread(cur->lchild, pre); Pre_Thread(cur->rchild, pre); } } //中序线索化 void In_Thread(BTree cur, BTree *pre) { if (cur) { In_Thread(cur->lchild, pre); printf("%c ", cur->data); if (cur->lchild==NULL) { cur->lchild = *pre; cur->ltag = 1; } if (cur->rtag == NULL) { cur->rtag = 1; } if (*pre && (*pre)->rtag == 1) { (*pre)->rchild = cur; } *pre = cur; In_Thread(cur->rchild, pre); } } //后序线索化 void Post_Thread(BTree cur, BTree *pre) { if (cur) { Post_Thread(cur->lchild, pre); Post_Thread(cur->rchild, pre); printf("%c ", cur->data); if (cur->lchild == NULL) { cur->lchild = *pre; cur->ltag = 1; } if (cur->rchild == NULL) { cur->rtag = 1; } if (*pre && (*pre)->rtag == 1) { (*pre)->rchild = cur; } *pre = cur; } } int main(void) { BTree T,p=NULL; T = Build_Tree(); Pre_Thread(T, &p); //In_Thread(T, &p); //Post_Thread(T, &p); return 0; }
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