为什么uint8_t 类型变量无利用c++进行打印

#include <cstdint>
#include <iostream>
#include <typeinfo>
int main()
{
 std::uint8_t uint8_num = 10;
 std::cout << "uint8_t num is " << uint8_num << std::endl; //无法打印
 std::cout << "after cast to unsigned, uint8_t num is " << unsigned(uint8_num) << std::endl; //能正常打印
 std::cout << "with a unary + operator, uint8_t num is " << +uint8_num << std::endl; //能正常打印
 std::cout << "type of '+uint8_num' is " << typeid(+uint8_num).name() << std::endl;
 return 0;
}

typedef signed char s8; 
typedef unsigned char u8; 
 
typedef signed short s16; 
typedef unsigned short u16; 
 
typedef signed int s32; 
typedef unsigned int u32; 
 
typedef signed long long s64; 
typedef unsigned long long u64; 

/* bsd */
typedef unsigned char u_char;
typedef unsigned short u_short;
typedef unsigned int u_int;
typedef unsigned long u_long;
/* sysv */
typedef unsigned char unchar;
typedef unsigned short ushort;
typedef unsigned int uint;
typedef unsigned long ulong;
#ifndef __BIT_TYPES_DEFINED__
#define __BIT_TYPES_DEFINED__
typedef __u8 u_int8_t;
typedef __s8 int8_t;
typedef __u16 u_int16_t;
typedef __s16 int16_t;
typedef __u32 u_int32_t;
typedef __s32 int32_t;
#endif /* !(__BIT_TYPES_DEFINED__) */
typedef __u8 uint8_t;
typedef __u16 uint16_t;
typedef __u32 uint32_t;
#if defined(__GNUC__)
typedef __u64 uint64_t;
typedef __u64 u_int64_t;
typedef __s64 int64_t;

#define _STDBOOL_H
#ifndef __cplusplus
#define bool _Bool
#define true 1
#define false 0
#else /* __cplusplus */
/* Supporting _Bool in C++ is a GCC extension. */
#define _Bool bool
#if __cplusplus < 201103L
/* Defining these macros in C++98 is a GCC extension. */
#define bool bool
#define false false
#define true true
#endif
#endif /* __cplusplus */
/* Signal that all the definitions are present. */
#define __bool_true_false_are_defined 1
#endif /* stdbool.h */