今天就跟大家聊聊有关如何从HGAME的pyc逆向来看手撸opcode,可能很多人都不太了解,为了让大家更加了解,小编给大家总结了以下内容,希望大家根据这篇文章可以有所收获。
红日安全:MoR03r
红日博客:http://sec-redclub.com/team/
[compile.h] /* Bytecode object */ typedef struct { PyObject_HEAD int co_argcount; /* #arguments, except *args */ int co_nlocals; /* #local variables */ int co_stacksize; /* #entries needed for evaluation stack */ int co_flags; /* CO_..., see below */ PyObject *co_code; /* instruction opcodes */ PyObject *co_consts; /* list (constants used) */ PyObject *co_names; /* list of strings (names used) */ PyObject *co_varnames; /* tuple of strings (local variable names) */ PyObject *co_freevars; /* tuple of strings (free variable names) */ PyObject *co_cellvars; /* tuple of strings (cell variable names) */ /* The rest doesn't count for hash/cmp */ PyObject *co_filename; /* string (where it was loaded from) */ PyObject *co_name; /* string (name, for reference) */ int co_firstlineno; /* first source line number */ PyObject *co_lnotab; /* string (encoding addr<->lineno mapping) */ } PyCodeObject;
In [1]: import dis,marshal In [2]: f=open('third.pyc') In [3]: f.read(4) Out[3]: '\x03\xf3\r\n' In [4]: f.read(4) Out[4]: '\xf1\xe1S\\' In [5]: code = marshal.load(f) In [6]: code.co_consts Out[6]: (-1, None, '+', '/', 'FcjTCgD1EffEm2rPC3bTyL5Wu2bKBI9KAZrwFgrUygHN', <code object encode at 0x7f0420ee7f30, file "third.py", line 7>, "Welcome to Processor's Python Classroom Part 3&4!\n", 'qi shi wo jiu shi lan cai ba liang dao ti fang zai yi qi.', "Now let's start the origin of Python!\n", 'Plz Input Your Flag:\n', 2, 0, 1, '', "You're right! ", "You're Wrong! ") In [7]: code.co_varnames Out[7]: () In [8]: code.co_names Out[8]: ('string', 'list', 'letters', 'digits', 'dec', 'encode', 'raw_input', 'enc', 'lst', 'reverse', 'len', 'llen', 'range', 'i', 'chr', 'ord', 'enc2', 'join', 'enc3') In [9]: code.co_code Out[9]: 'q\x03\x00q\t\x00d\x0f\x00q\x0e\x00Gdd\x00\x00d\x01\x00l\x00\x00Z\x00\x00e\x01\x00e\x00\x00j\x02\x00\x83\x01\x00e\x01\x00e\x00\x00j\x03\x00\x83\x01\x00\x17d\x02\x00d\x03\x00g\x02\x00\x17Z\x02\x00d\x04\x00Z\x04\x00d\x05\x00\x84\x00\x00Z\x05\x00d\x06\x00GHd\x07\x00GHd\x08\x00GHd\t\x00GHe\x06\x00\x83\x00\x00Z\x07\x00e\x01\x00e\x07\x00\x83\x01\x00Z\x08\x00e\x08\x00j\t\x00\x83\x00\x00\x01e\n\x00e\x08\x00\x83\x01\x00Z\x0b\x00xc\x00e\x0c\x00e\x0b\x00\x83\x01\x00D]U\x00Z\r\x00e\r\x00d\n\x00\x16d\x0b\x00k\x02\x00r\xc4\x00e\x0e\x00e\x0f\x00e\x08\x00e\r\x00\x19\x83\x01\x00d\n\x00\x18\x83\x01\x00e\x08\x00e\r\x00<n\x00\x00e\x0e\x00e\x0f\x00e\x08\x00e\r\x00\x19\x83\x01\x00d\x0c\x00\x17\x83\x01\x00e\x08\x00e\r\x00<q\x8d\x00Wd\r\x00Z\x10\x00e\x10\x00j\x11\x00e\x08\x00\x83\x01\x00Z\x10\x00e\x05\x00e\x10\x00\x83\x01\x00Z\x12\x00e\x12\x00e\x04\x00k\x02\x00r\x1b\x01d\x0e\x00GHn\x05\x00d\x0f\x00GHd\x01\x00S'
使用dis
库对co_code
进行解释
In [10]: dis.dis(code.co_code) 0 JUMP_ABSOLUTE 3 >> 3 JUMP_ABSOLUTE 9 6 LOAD_CONST 15 (15) >> 9 JUMP_ABSOLUTE 14 12 PRINT_ITEM 13 LOAD_CONST 100 (100) 16 STOP_CODE 17 LOAD_CONST 1 (1) 20 IMPORT_NAME 0 (0) 23 STORE_NAME 0 (0) 26 LOAD_NAME 1 (1) 29 LOAD_NAME 0 (0) 32 LOAD_ATTR 2 (2) 35 CALL_FUNCTION 1 38 LOAD_NAME 1 (1) 41 LOAD_NAME 0 (0) 44 LOAD_ATTR 3 (3) 47 CALL_FUNCTION 1 50 BINARY_ADD 51 LOAD_CONST 2 (2) 54 LOAD_CONST 3 (3) 57 BUILD_LIST 2 60 BINARY_ADD 61 STORE_NAME 2 (2) 64 LOAD_CONST 4 (4) 67 STORE_NAME 4 (4) 70 LOAD_CONST 5 (5) 73 MAKE_FUNCTION 0 76 STORE_NAME 5 (5) 79 LOAD_CONST 6 (6) 82 PRINT_ITEM 83 PRINT_NEWLINE 84 LOAD_CONST 7 (7) 87 PRINT_ITEM 88 PRINT_NEWLINE 89 LOAD_CONST 8 (8) 92 PRINT_ITEM 93 PRINT_NEWLINE 94 LOAD_CONST 9 (9) 97 PRINT_ITEM 98 PRINT_NEWLINE 99 LOAD_NAME 6 (6) 102 CALL_FUNCTION 0 105 STORE_NAME 7 (7) 108 LOAD_NAME 1 (1) 111 LOAD_NAME 7 (7) 114 CALL_FUNCTION 1 117 STORE_NAME 8 (8) 120 LOAD_NAME 8 (8) 123 LOAD_ATTR 9 (9) 126 CALL_FUNCTION 0 129 POP_TOP 130 LOAD_NAME 10 (10) 133 LOAD_NAME 8 (8) 136 CALL_FUNCTION 1 139 STORE_NAME 11 (11) 142 SETUP_LOOP 99 (to 244) 145 LOAD_NAME 12 (12) 148 LOAD_NAME 11 (11) 151 CALL_FUNCTION 1 154 GET_ITER 155 FOR_ITER 85 (to 243) 158 STORE_NAME 13 (13) 161 LOAD_NAME 13 (13) 164 LOAD_CONST 10 (10) 167 BINARY_MODULO 168 LOAD_CONST 11 (11) 171 COMPARE_OP 2 (==) 174 POP_JUMP_IF_FALSE 196 177 LOAD_NAME 14 (14) 180 LOAD_NAME 15 (15) 183 LOAD_NAME 8 (8) 186 LOAD_NAME 13 (13) 189 BINARY_SUBSCR 190 CALL_FUNCTION 1 193 LOAD_CONST 10 (10) >> 196 BINARY_SUBTRACT 197 CALL_FUNCTION 1 200 LOAD_NAME 8 (8) 203 LOAD_NAME 13 (13) 206 STORE_SUBSCR 207 JUMP_FORWARD 0 (to 210) >> 210 LOAD_NAME 14 (14) 213 LOAD_NAME 15 (15) 216 LOAD_NAME 8 (8) 219 LOAD_NAME 13 (13) 222 BINARY_SUBSCR 223 CALL_FUNCTION 1 226 LOAD_CONST 12 (12) 229 BINARY_ADD 230 CALL_FUNCTION 1 233 LOAD_NAME 8 (8) 236 LOAD_NAME 13 (13) 239 STORE_SUBSCR 240 JUMP_ABSOLUTE 141 >> 243 POP_BLOCK >> 244 LOAD_CONST 13 (13) 247 STORE_NAME 16 (16) 250 LOAD_NAME 16 (16) 253 LOAD_ATTR 17 (17) 256 LOAD_NAME 8 (8) 259 CALL_FUNCTION 1 262 STORE_NAME 16 (16) 265 LOAD_NAME 5 (5) 268 LOAD_NAME 16 (16) 271 CALL_FUNCTION 1 274 STORE_NAME 18 (18) 277 LOAD_NAME 18 (18) 280 LOAD_NAME 4 (4) >> 283 COMPARE_OP 2 (==) 286 POP_JUMP_IF_FALSE 283 289 LOAD_CONST 14 (14) 292 PRINT_ITEM 293 PRINT_NEWLINE 294 JUMP_FORWARD 5 (to 302) 297 LOAD_CONST 15 (15) 300 PRINT_ITEM 301 PRINT_NEWLINE >> 302 LOAD_CONST 1 (1) 305 RETURN_VALUE
刚开始走了一些弯路,通读了opcode
,结果发现并不需要,只要将反uncompyle2
的部分去掉,修改co_code
长度即可正常反编译,期望修改后的opcode
首行为
0 LOAD_CONST 0(0) 1 LOAD_CONST 1(1) ...
使用hexdump
查看文件
0x64 操作为LOAD_CONST,用法举例:LOAD_CONST 1 HEX: 640100
0x71 操作为JUMP_ABSOLUTE,用法举例:JUMP_ABSOLUTE 14 HEX: 710e00
0x65 操作为LOAD_NAME,用法举例:LOAD_NAME 1 HEX: 650100
...
通过opcode
及hexdump
可以确定,当前co_code
长度为0x132
(此处为小端显示,0x1a1b
位置),0x1e
到0x2c
(左闭右开)这部分为混淆代码,直接从16进制数据中删除,然后修改co_code
长度为0x132-(0x2c-0x1e)
,即改为24 01
,保存代码
In [1]: with open('third.pyc','r') as f: ...: dt = f.read() ...: In [2]: dt = dt[:0x1a]+'\x24'+dt[0x1b:0x1e]+dt[0x2c:] In [3]: with open('third_test2.pyc', 'w') as f: ...: f.write(dt) ...:
然后使用uncompyle2 third_test2.pyc > third_source.py
进行反编译
源码如下:
# 2019.02.16 14:17:20 CST #Embedded file name: third.py import string letters = list(string.letters) + list(string.digits) + ['+', '/'] dec = 'FcjTCgD1EffEm2rPC3bTyL5Wu2bKBI9KAZrwFgrUygHN' def encode(input_str): str_ascii_list = [ '{:0>8}'.format(str(bin(ord(i))).replace('0b', '')) for i in input_str ] output_str = '' equal_num = 0 while str_ascii_list: temp_list = str_ascii_list[:3] if len(temp_list) != 3: while len(temp_list) < 3: equal_num += 1 temp_list += ['00000000'] temp_str = ''.join(temp_list) temp_str_list = [ temp_str[x:x + 6] for x in [0, 6, 12, 18] ] temp_str_list = [ int(x, 2) for x in temp_str_list ] if equal_num: temp_str_list = temp_str_list[0:4 - equal_num] output_str += ''.join([ letters[x] for x in temp_str_list ]) str_ascii_list = str_ascii_list[3:] output_str = output_str + '=' * equal_num return output_str print "Welcome to Processor's Python Classroom Part 3&4!\n" print 'qi shi wo jiu shi lan cai ba liang dao ti fang zai yi qi.' print "Now let's start the origin of Python!\n" print 'Plz Input Your Flag:\n' enc = raw_input() lst = list(enc) lst.reverse() llen = len(lst) for i in range(llen): if i % 2 == 0: lst[i] = chr(ord(lst[i]) - 2) lst[i] = chr(ord(lst[i]) + 1) enc2 = '' enc2 = enc2.join(lst) enc3 = encode(enc2) if enc3 == dec: print "You're right! " else: print "You're Wrong! " # +++ okay decompyling third_test2.pyc # decompiled 1 files: 1 okay, 0 failed, 0 verify failed # 2019.02.16 14:17:21 CST
至此,代码已经还原,剩下的题目就很简单了。
encode
函数实现了一个base64
,这里有一点点坑,这里的base64
编码范围为abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789+/
,并非原生的ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/
,直接转换一下就好
solve.py↓
#!/usr/bin/python # -*- coding: utf-8 -*- def decode(input_str): output_str = '' for i in input_str: if ord(i)>57 and ord(i)<91: output_str += i.lower() elif ord(i)>91: output_str += i.upper() else: output_str += i lst = list(output_str.decode('base64')) llen = len(lst) for i in range(llen): lst[i] = chr(ord(lst[i]) - 1) if i % 2 == 0: lst[i] = chr(ord(lst[i]) + 2) lst.reverse() return ''.join(lst) if __name__ == '__main__': dec = 'FcjTCgD1EffEm2rPC3bTyL5Wu2bKBI9KAZrwFgrUygHN' print decode(dec)
看完上述内容,你们对如何从HGAME的pyc逆向来看手撸opcode有进一步的了解吗?如果还想了解更多知识或者相关内容,请关注亿速云行业资讯频道,感谢大家的支持。
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