现在,我们将发送一些字符串,把这些字符串当作复杂的任务。我们并没有一个真实的复杂任务,类似于图片大小被调整或 pdf 文件被渲染,所以我们通过 sleep () 方法来模拟这种情况。我们在字符串中加上点号(.)来表示任务的复杂程度,一个点(.)将会耗时 1 秒钟。比如 “Hello…” 就会耗时 3 秒钟。
如果您尚未设置项目,请参阅第一个教程中的设置。我们将遵循与第一个教程相同的模式:创建一个包(tut2)并创建 Tut2Config、Tut2Receiver 和 Tut2Sender。
代码整合
首先创建一个新的包(tut2),我们将在这里放置我们的三个类。在配置类 Tut2Config 中,我们设置了两个配置文件 ——tut2 和 work-queues。我们利用 Spring 来将队列 Queue 暴露为一个 bean。我们配置消费者,并定义两个 bean 以对应于上图中的工作进程 receiver1 和 receiver2。
配置类
@Profile({"tut2", "work-queues"})
@Configuration
public class Tut2Config {
@Bean
public Queue queue() {
return new Queue("work-queues");
}
/**
* 定义两个消费者,并且给了他们不同的标识
*/
@Profile ("receiver")
private static class ReceiverConfig {
@Bean
public Tut2Receiver receiver1() {
return new Tut2Receiver(1);
}
@Bean
public Tut2Receiver receiver2() {
return new Tut2Receiver(2);
}
}
@Profile("sender")
@Bean
public Tut2Sender sender() {
return new Tut2Sender();
}
}
生产者
我们简单修改一下生产者的代码,以添加点号(.)的方式来人为的增加该任务的时长,字符串中的每个点号(.)都会增加 1s 的耗时。
public class Tut2Sender {
@Autowired
private AmqpTemplate template;
@Autowired
private Queue queue;
int dots = 0;
int count = 0;
@Scheduled(fixedDelay = 1000, initialDelay = 500)
public void send(){
StringBuilder builder = new StringBuilder("Hello");
if (dots++ == 3) {
dots = 1;
}
for (int i = 0; i < dots; i++) {
builder.append('.');
}
builder.append(Integer.toString(++count));
String message = builder.toString();
template.convertAndSend(queue.getName(), message);
System.out.println(" [x] Sent '" + message + "'");
}
}
消费者
我们的消费者 Tut2Receiver 通过 doWork () 方法模拟了一个耗时的虚假任务,它需要为消息体中每一个点号(.)模拟 1 秒钟的操作。并且我们为消费者增加了一个实例编号,以知道是哪个实例消费了消息和处理的时长。
@RebbitListener(queues = "work-queues")
public class Tut2Receiver {
private int instance;
public Tut2Receiver(int instance) {
this.instance = instance;
}
@RabbitHandler
public void receive(String in) throws InterruptedException {
StopWatch watch = new StopWatch();
watch.start();
System.out.println("instance " + this.instance +
" [x] Received '" + in + "'");
doWork(in);
watch.stop();
System.out.println("instance " + this.instance +
" [x] Done in " + watch.getTotalTimeSeconds() + "s");
}
private void doWork(String in) throws InterruptedException {
for (char ch : in.toCharArray()) {
if (ch == '.') {
Thread.sleep(1000);
}
}
}
}
运行
maven 编译
mvn clean package -Dmaven.test.skip=true
运行
java -jar target/rabbitmq-tutorial-0.0.1-SNAPSHOT.jar --spring.profiles.active=tut2,sender --tutorial.client.duration=60000
java -jar target/rabbitmq-tutorial-0.0.1-SNAPSHOT.jar --spring.profiles.active=tut2,receiver --tutorial.client.duration=60000
输出
// Sender
Ready … running for 10000ms
[x] Sent ‘Hello.1’
[x] Sent ‘Hello…2’
[x] Sent ‘Hello…3’
[x] Sent ‘Hello.4’
[x] Sent ‘Hello…5’
[x] Sent ‘Hello…6’
[x] Sent ‘Hello.7’
[x] Sent ‘Hello…8’
[x] Sent ‘Hello…9’
// Receiver
Ready … running for 10000ms
instance 1 [x] Received ‘Hello.1’
instance 2 [x] Received ‘Hello…2’
instance 1 [x] Done in 1.005s
instance 1 [x] Received ‘Hello…3’
instance 2 [x] Done in 2.007s
instance 2 [x] Received ‘Hello.4’
instance 2 [x] Done in 1.005s
instance 1 [x] Done in 3.01s
instance 1 [x] Received ‘Hello…5’
instance 2 [x] Received ‘Hello…6’
instance 1 [x] Done in 2.006s
instance 1 [x] Received ‘Hello.7’
instance 1 [x] Done in 1.002s
instance 1 [x] Received ‘Hello…9’
instance 2 [x] Done in 3.01s
instance 2 [x] Received ‘Hello…8’
prefetch
从消费者这端的输出可以看出来,instance 1 得到的任务编号始终是奇数(Hello.1,Hello…3,Hello…5,Hello.7),而 instance 2 得到的任务编号始终是偶数。了解springcloud架构可以加求求:三五三六二四七二五九
如果感觉这次的输出只是巧合,可以多试几次或通过 --tutorial.client.duration= 调整时长得到更多的输出,而结果肯定都是一样的。
这里设计的问题就是之前在基础概念里讲到的调度策略的问题了。要实现公平调度(Fair dispatch)就是设置 prefetch 的值,实现方式有两种。
全局设置
在 application.yml 中设置 spring.rabbitmq.listener.simple.prefetch=1 即可,这会影响到本 Spring Boot 应用中所有使用默认 SimpleRabbitListenerContainerFactory 的消费者。
网上很多人说改配置 pring.rabbitmq.listener.prefetc,实测已经无效,应该是版本的问题。我所使用的版本(RabbitMQ:3.7.4,Spring Boot: 2.0.1.RELEASE),除了 spring.rabbitmq.listener.simple.prefetch,还有一个 spring.rabbitmq.listener.direct.prefetch 可以配置。
改了配置后再运行,可以看到 instance 1 可以获取到”Hello…6”、”Hello…12” 了。
Ready … running for 60000ms
instance 1 [x] Received ‘Hello.1’
instance 2 [x] Received ‘Hello…2’
instance 1 [x] Done in 1.004s
instance 1 [x] Received ‘Hello…3’
instance 2 [x] Done in 2.008s
instance 2 [x] Received ‘Hello.4’
instance 2 [x] Done in 1.004s
instance 2 [x] Received ‘Hello…5’
instance 1 [x] Done in 3.012s
instance 1 [x] Received ‘Hello…6’
instance 2 [x] Done in 2.007s
instance 2 [x] Received ‘Hello.7’
instance 2 [x] Done in 1.004s
instance 2 [x] Received ‘Hello…8’
instance 1 [x] Done in 3.011s
instance 1 [x] Received ‘Hello…9’
instance 2 [x] Done in 2.007s
instance 2 [x] Received ‘Hello.10’
instance 2 [x] Done in 1.006s
instance 2 [x] Received ‘Hello…11’
instance 1 [x] Done in 3.01s
instance 1 [x] Received ‘Hello…12’
特定消费者
上边是改了全局的消费者,如果只针对特定的消费者的话,又怎么处理呢?
我们可以通过自定义 RabbitListenerContainerFactory 来实现。
@Bean
public RabbitListenerContainerFactory<SimpleMessageListenerContainer> prefetchOneRabbitListenerContainerFactory(ConnectionFactory rabbitConnectionFactory) {
SimpleRabbitListenerContainerFactory factory = new SimpleRabbitListenerContainerFactory();
factory.setConnectionFactory(rabbitConnectionFactory);
factory.setPrefetchCount(1);
return factory;
}
然后在特定的消费者上指定 containerFactory
@RebbitListener(queues = "hello", containerFactory = "prefetchTenRabbitListenerContainerFactory")
public void receive(String in) {
System.out.println(" [x] Received '" + in + "'")
}
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原文链接:http://blog.itpub.net/69952307/viewspace-2678699/