本篇内容介绍了“java List中如何筛选list中相同的值和筛选不同的值”的有关知识，在实际案例的操作过程中，不少人都会遇到这样的困境，接下来就让小编带领大家学习一下如何处理这些情况吧！希望大家仔细阅读，能够学有所成！
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public class People {
private String id;
private String somethingElse;
public People() {
}
public People(String id, String somethingElse) {
this.id = id;
this.somethingElse = somethingElse;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getSomethingElse() {
return somethingElse;
}
public void setSomethingElse(String somethingElse) {
this.somethingElse = somethingElse;
}
@Override
public String toString() {
return "People{" +
"id='" + id + '\'' +
", somethingElse='" + somethingElse + '\'' +
'}';
}
}people实体类和student实体类
People类
student
public class Student {
private String id;
private String idCard;
private String somethingElse;
public Student() {
}
public Student(String id, String idCard, String somethingElse) {
this.id = id;
this.idCard = idCard;
this.somethingElse = somethingElse;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getIdCard() {
return idCard;
}
public void setIdCard(String idCard) {
this.idCard = idCard;
}
public String getSomethingElse() {
return somethingElse;
}
public void setSomethingElse(String somethingElse) {
this.somethingElse = somethingElse;
}
@Override
public String toString() {
return "Student{" +
"id='" + id + '\'' +
", idCard='" + idCard + '\'' +
", somethingElse='" + somethingElse + '\'' +
'}';
}
}测试类
public static void main(String[] args) throws Exception{
//初始化数据
List<Student> studentList = new ArrayList(){{
add(new Student("1", "11", "111")) ;
add(new Student("2", "22", "222"));
add(new Student("3", "33", "333"));
}};
List<People> peopleList = new ArrayList(){
{
add(new People("11", "111"));
add(new People("222", "222"));
add(new People("33", "333"));
}};
//获取相同字段内容，转化为set
Set<String> ids = peopleList
.stream()
.map(People::getId)
.collect(Collectors.toSet());//过滤重复内容
List<Student> result = studentList
.stream()
.filter(e -> ids.contains(e.getIdCard()))
.collect(Collectors.toList());
System.out.println(result);
//获取相同字段内容，转化为set
Set<String> ids = peopleList
.stream()
.map(People::getId)
.collect(Collectors.toSet());//过滤重复内容
List<Student> result = studentList
.stream()
.filter(e -> !ids.contains(e.getIdCard()))
.collect(Collectors.toList());
System.out.println(result);
}“java List中如何筛选list中相同的值和筛选不同的值”的内容就介绍到这里了，感谢大家的阅读。如果想了解更多行业相关的知识可以关注亿速云网站，小编将为大家输出更多高质量的实用文章！
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原文链接：https://my.oschina.net/javazyw/blog/5015148
