这篇文章主要介绍了java怎么筛选list中相同的值和筛选不同的值的相关知识,内容详细易懂,操作简单快捷,具有一定借鉴价值,相信大家阅读完这篇java怎么筛选list中相同的值和筛选不同的值文章都会有所收获,下面我们一起来看看吧。
代码如下:
public class People {
private String id;
private String somethingElse;
public People() {
}
public People(String id, String somethingElse) {
this.id = id;
this.somethingElse = somethingElse;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getSomethingElse() {
return somethingElse;
}
public void setSomethingElse(String somethingElse) {
this.somethingElse = somethingElse;
}
@Override
public String toString() {
return "People{" +
"id='" + id + '\'' +
", somethingElse='" + somethingElse + '\'' +
'}';
}
}
people实体类和student实体类
People类
student
public class Student {
private String id;
private String idCard;
private String somethingElse;
public Student() {
}
public Student(String id, String idCard, String somethingElse) {
this.id = id;
this.idCard = idCard;
this.somethingElse = somethingElse;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getIdCard() {
return idCard;
}
public void setIdCard(String idCard) {
this.idCard = idCard;
}
public String getSomethingElse() {
return somethingElse;
}
public void setSomethingElse(String somethingElse) {
this.somethingElse = somethingElse;
}
@Override
public String toString() {
return "Student{" +
"id='" + id + '\'' +
", idCard='" + idCard + '\'' +
", somethingElse='" + somethingElse + '\'' +
'}';
}
}
测试类
public static void main(String[] args) throws Exception{
//初始化数据
List<Student> studentList = new ArrayList(){{
add(new Student("1", "11", "111")) ;
add(new Student("2", "22", "222"));
add(new Student("3", "33", "333"));
}};
List<People> peopleList = new ArrayList(){
{
add(new People("11", "111"));
add(new People("222", "222"));
add(new People("33", "333"));
}};
//获取相同字段内容,转化为set
Set<String> ids = peopleList
.stream()
.map(People::getId)
.collect(Collectors.toSet());//过滤重复内容
List<Student> result = studentList
.stream()
.filter(e -> ids.contains(e.getIdCard()))
.collect(Collectors.toList());
System.out.println(result);
//获取相同字段内容,转化为set
Set<String> ids = peopleList
.stream()
.map(People::getId)
.collect(Collectors.toSet());//过滤重复内容
List<Student> result = studentList
.stream()
.filter(e -> !ids.contains(e.getIdCard()))
.collect(Collectors.toList());
System.out.println(result);
}
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原文链接:https://my.oschina.net/u/4586369/blog/4403436