这篇文章主要介绍“Apache下Flink transformation的用法”，在日常操作中，相信很多人在Apache下Flink transformation的用法问题上存在疑惑，小编查阅了各式资料，整理出简单好用的操作方法，希望对大家解答”Apache下Flink transformation的用法”的疑惑有所帮助！接下来，请跟着小编一起来学习吧！
新建一个Object
计算
安全
数据库
网络和加速
企业服务
object DataSetTransformationApp {
def main(args: Array[String]): Unit = {
val environment = ExecutionEnvironment.getExecutionEnvironment
}
def mapFunction(env: ExecutionEnvironment): Unit = {
val data = env.fromCollection(List(1,2,3,4,5,6,7,8,9,10))
}
}这里的数据源是一个1到10的list集合。Map的原理是：假设data数据集中有N个元素，将每一个元素进行转化：
data.map { x => x.toInt }好比：y=f(x)
// 对data中的每一个元素都去做一个+1操作
data.map((x:Int) => x + 1 ).print()然后对每一个元素都做一个+1操作。
简单写法：
如果这个里面只有一个元素，就可以直接写成下面形式：
data.map((x) => x + 1).print()更简洁的写法：
data.map(x => x + 1).print()更简洁的方法：
data.map(_ + 1).print()输出结果：
2 3 4 5 6 7 8 9 10 11
public static void main(String[] args) throws Exception {
ExecutionEnvironment executionEnvironment = ExecutionEnvironment.getExecutionEnvironment();
mapFunction(executionEnvironment);
}
public static void mapFunction(ExecutionEnvironment executionEnvironment) throws Exception {
List<String> list = new ArrayList<>();
for (int i = 1; i <= 10; i++) {
list.add(i + "");
}
DataSource<String> data = executionEnvironment.fromCollection(list);
data.map(new MapFunction<String, Integer>() {
public Integer map(String input) {
return Integer.parseInt(input) + 1;
}
}).print();
}因为我们定义的List是一个String的泛型，因此MapFunction的泛型是<String, Integer>，第一个参数表示输入的类型，第二个参数表示输出是一个Integer类型。
将每个元素执行+1操作，并取出大于5的元素。
def filterFunction(env: ExecutionEnvironment): Unit = {
val data = env.fromCollection(List(1, 2, 3, 4, 5, 6, 7, 8, 9, 10))
data.map(_ + 1).filter(_ > 5).print()
}filter只会返回满足条件的记录。
public static void filterFunction(ExecutionEnvironment env) throws Exception {
List<Integer> list = new ArrayList<>();
for (int i = 1; i <= 10; i++) {
list.add(i);
}
DataSource<Integer> data = env.fromCollection(list);
data.map(new MapFunction<Integer, Integer>() {
public Integer map(Integer input) {
return input + 1;
}
}).filter(new FilterFunction<Integer>() {
@Override
public boolean filter(Integer input) throws Exception {
return input > 5;
}
}).print();
}map function 与 MapPartition function有什么区别？
需求：DataSource 中有100个元素,把结果存储在数据库中
如果使用map function ，那么实现方法如下：
// DataSource 中有100个元素,把结果存储在数据库中
def mapPartitionFunction(env: ExecutionEnvironment): Unit = {
val students = new ListBuffer[String]
for (i <- 1 to 100) {
students.append("Student" + i)
}
val data = env.fromCollection(students)
data.map(x=>{
// 每一个元素要存储到数据库中去，肯定需要先获取到connection
val connection = DBUtils.getConnection()
println(connection + " ... ")
// TODO .... 保存数据到DB
DBUtils.returnConnection(connection)
}).print()
}打印结果，将会打印100个获取DBUtils.getConnection()的请求。如果数据量增多，显然不停的获取连接是不现实的。
因此MapPartition就应运而生了，转换一个分区里面的数据，也就是说一个分区中的数据调用一次。
因此要首先设置分区：
val data = env.fromCollection(students).setParallelism(4)设置4个分区，也就是并行度，然后使用mapPartition来处理：
data.mapPartition(x => {
val connection = DBUtils.getConnection()
println(connection + " ... ")
// TODO .... 保存数据到DB
DBUtils.returnConnection(connection)
x
}).print()那么就会的到4次连接请求，每一个分区获取一个connection。
public static void mapPartitionFunction(ExecutionEnvironment env) throws Exception {
List<String> list = new ArrayList<>();
for (int i = 1; i <= 100; i++) {
list.add("student:" + i);
}
DataSource<String> data = env.fromCollection(list);
/*data.map(new MapFunction<String, String>() {
@Override
public String map(String input) throws Exception {
String connection = DBUtils.getConnection();
System.out.println("connection = [" + connection + "]");
DBUtils.returnConnection(connection);
return input;
}
}).print();*/
data.mapPartition(new MapPartitionFunction<String, Object>() {
@Override
public void mapPartition(Iterable<String> values, Collector<Object> out) throws Exception {
String connection = DBUtils.getConnection();
System.out.println("connection = [" + connection + "]");
DBUtils.returnConnection(connection);
}
}).print();
}first表示获取前几个，groupBy表示分组，sortGroup表示分组内排序
def firstFunction(env:ExecutionEnvironment): Unit = {
val info = ListBuffer[(Int, String)]()
info.append((1, "hadoop"))
info.append((1, "spark"))
info.append((1, "flink"))
info.append((2, "java"))
info.append((2, "springboot"))
info.append((3, "linux"))
info.append((4, "vue"))
val data = env.fromCollection(info)
data.first(3).print()
//输出:(1,hadoop)
//(1,spark)
//(1,flink)
data.groupBy(0).first(2).print()//根据第一个字段分组，每个分组获取前两个数据
//(3,linux)
//(1,hadoop)
//(1,spark)
//(2,java)
//(2,springboot)
//(4,vue)
data.groupBy(0).sortGroup(1, Order.ASCENDING).first(2).print() //根据第一个字段分组，然后在分组内根据第二个字段升序排序，并取出前两个数据
//输出(3,linux)
//(1,flink)
//(1,hadoop)
//(2,java)
//(2,springboot)
//(4,vue)
} public static void firstFunction(ExecutionEnvironment env) throws Exception {
List<Tuple2<Integer, String>> info = new ArrayList<>();
info.add(new Tuple2<>(1, "hadoop"));
info.add(new Tuple2<>(1, "spark"));
info.add(new Tuple2<>(1, "flink"));
info.add(new Tuple2<>(2, "java"));
info.add(new Tuple2<>(2, "springboot"));
info.add(new Tuple2<>(3, "linux"));
info.add(new Tuple2<>(4, "vue"));
DataSource<Tuple2<Integer, String>> data = env.fromCollection(info);
data.first(3).print();
data.groupBy(0).first(2).print();
data.groupBy(0).sortGroup(1, Order.ASCENDING).first(2).print();
}获取一个元素，然后产生0个、1个或多个元素
def flatMapFunction(env: ExecutionEnvironment): Unit = {
val info = ListBuffer[(String)]()
info.append("hadoop,spark");
info.append("hadoop,flink");
info.append("flink,flink");
val data = env.fromCollection(info)
data.flatMap(_.split(",")).print()
}输出：
hadoop spark hadoop flink flink flink
FlatMap将每个元素都用逗号分割，然后变成多个。
经典例子：
data.flatMap(_.split(",")).map((_,1)).groupBy(0).sum(1).print()将每个元素用逗号分割，然后每个元素做map，然后根据第一个字段分组，然后根据第二个字段求和。
输出结果如下：
(hadoop,2)
(flink,3)
(spark,1)同样实现一个经典案例wordcount
public static void flatMapFunction(ExecutionEnvironment env) throws Exception {
List<String> info = new ArrayList<>();
info.add("hadoop,spark");
info.add("hadoop,flink");
info.add("flink,flink");
DataSource<String> data = env.fromCollection(info);
data.flatMap(new FlatMapFunction<String, String>() {
@Override
public void flatMap(String input, Collector<String> out) throws Exception {
String[] splits = input.split(",");
for(String split: splits) {
//发送出去
out.collect(split);
}
}
}).map(new MapFunction<String, Tuple2<String, Integer>>() {
@Override
public Tuple2<String, Integer> map(String value) throws Exception {
return new Tuple2<>(value,1);
}
}).groupBy(0).sum(1).print();
}去重操作
def distinctFunction(env: ExecutionEnvironment): Unit = {
val info = ListBuffer[(String)]()
info.append("hadoop,spark");
info.append("hadoop,flink");
info.append("flink,flink");
val data = env.fromCollection(info)
data.flatMap(_.split(",")).distinct().print()
}这样就将每一个元素都做了去重操作。输出如下：
hadoop flink spark
public static void distinctFunction(ExecutionEnvironment env) throws Exception {
List<String> info = new ArrayList<>();
info.add("hadoop,spark");
info.add("hadoop,flink");
info.add("flink,flink");
DataSource<String> data = env.fromCollection(info);
data.flatMap(new FlatMapFunction<String, String>() {
@Override
public void flatMap(String input, Collector<String> out) throws Exception {
String[] splits = input.split(",");
for(String split: splits) {
//发送出去
out.collect(split);
}
}
}).distinct().print();
}Joins two data sets by creating all pairs of elements that are equal on their keys. Optionally uses a JoinFunction to turn the pair of elements into a single element, or a FlatJoinFunction to turn the pair of elements into arbitrarily many (including none) elements. See the keys section to learn how to define join keys.
result = input1.join(input2) .where(0) // key of the first input (tuple field 0) .equalTo(1); // key of the second input (tuple field 1)
表示第一个tuple input1中的第0个字段，与第二个tuple input2中的第一个字段进行join。
def joinFunction(env: ExecutionEnvironment): Unit = {
val info1 = ListBuffer[(Int, String)]() //编号 名字
info1.append((1, "hadoop"))
info1.append((2, "spark"))
info1.append((3, "flink"))
info1.append((4, "java"))
val info2 = ListBuffer[(Int, String)]() //编号 城市
info2.append((1, "北京"))
info2.append((2, "上海"))
info2.append((3, "深圳"))
info2.append((5, "广州"))
val data1 = env.fromCollection(info1)
val data2 = env.fromCollection(info2)
data1.join(data2).where(0).equalTo(0).apply((first, second)=>{
(first._1, first._2, second._2)
}).print()
}输出结果如下：
(3,flink,深圳)
(1,hadoop,北京)
(2,spark,上海) public static void joinFunction(ExecutionEnvironment env) throws Exception {
List<Tuple2<Integer, String>> info1 = new ArrayList<>(); //编号 名字
info1.add(new Tuple2<>(1, "hadoop"));
info1.add(new Tuple2<>(2, "spark"));
info1.add(new Tuple2<>(3, "flink"));
info1.add(new Tuple2<>(4, "java"));
List<Tuple2<Integer, String>> info2 = new ArrayList<>(); //编号 城市
info2.add(new Tuple2<>(1, "北京"));
info2.add(new Tuple2<>(2, "上海"));
info2.add(new Tuple2<>(3, "深圳"));
info2.add(new Tuple2<>(5, "广州"));
DataSource<Tuple2<Integer, String>> data1 = env.fromCollection(info1);
DataSource<Tuple2<Integer, String>> data2 = env.fromCollection(info2);
data1.join(data2).where(0).equalTo(0).with(new JoinFunction<Tuple2<Integer, String>, Tuple2<Integer, String>, Tuple3<Integer, String, String>>() {
@Override
public Tuple3<Integer, String, String> join(Tuple2<Integer, String> first, Tuple2<Integer, String> second) throws Exception {
return new Tuple3<Integer, String, String>(first.f0, first.f1,second.f1);
}
}).print();
}Tuple2<Integer, String>, Tuple2<Integer, String>表示两个输入的集合，Tuple3<Integer, String, String>>表示输出的Tuple3
上面讲的join是内连接，这个OuterJoin是外连接，包括左外连接，右外连接，全连接在两个数据集上。
def outJoinFunction(env: ExecutionEnvironment): Unit = {
val info1 = ListBuffer[(Int, String)]() //编号 名字
info1.append((1, "hadoop"))
info1.append((2, "spark"))
info1.append((3, "flink"))
info1.append((4, "java"))
val info2 = ListBuffer[(Int, String)]() //编号 城市
info2.append((1, "北京"))
info2.append((2, "上海"))
info2.append((3, "深圳"))
info2.append((5, "广州"))
val data1 = env.fromCollection(info1)
val data2 = env.fromCollection(info2)
data1.leftOuterJoin(data2).where(0).equalTo(0).apply((first, second) => {
if (second == null) {
(first._1, first._2, "-")
}else {
(first._1, first._2, second._2)
}
}).print() //左外连接 把左边的所有数据展示出来
}左外连接，当左边的数据在右边没有对应的数据时，需要进行处理，否则会出现空指针异常。输出如下：
(3,flink,深圳)
(1,hadoop,北京)
(2,spark,上海)
(4,java,-)右外连接：
data1.rightOuterJoin(data2).where(0).equalTo(0).apply((first, second) => {
if (first == null) {
(second._1, "-", second._2)
}else {
(first._1, first._2, second._2)
}
}).print()右外连接，输出：
(3,flink,深圳)
(1,hadoop,北京)
(5,-,广州)
(2,spark,上海)全连接：
data1.fullOuterJoin(data2).where(0).equalTo(0).apply((first, second) => {
if (first == null) {
(second._1, "-", second._2)
}else if (second == null){
(second._1, "-", second._2)
} else {
(first._1, first._2, second._2)
}
}).print()(3,flink,深圳)
(1,hadoop,北京)
(5,-,广州)
(2,spark,上海)
(4,java,-)左外连接：
public static void outjoinFunction(ExecutionEnvironment env) throws Exception {
List<Tuple2<Integer, String>> info1 = new ArrayList<>(); //编号 名字
info1.add(new Tuple2<>(1, "hadoop"));
info1.add(new Tuple2<>(2, "spark"));
info1.add(new Tuple2<>(3, "flink"));
info1.add(new Tuple2<>(4, "java"));
List<Tuple2<Integer, String>> info2 = new ArrayList<>(); //编号 城市
info2.add(new Tuple2<>(1, "北京"));
info2.add(new Tuple2<>(2, "上海"));
info2.add(new Tuple2<>(3, "深圳"));
info2.add(new Tuple2<>(5, "广州"));
DataSource<Tuple2<Integer, String>> data1 = env.fromCollection(info1);
DataSource<Tuple2<Integer, String>> data2 = env.fromCollection(info2);
data1.leftOuterJoin(data2).where(0).equalTo(0).with(new JoinFunction<Tuple2<Integer, String>, Tuple2<Integer, String>, Tuple3<Integer, String, String>>() {
@Override
public Tuple3<Integer, String, String> join(Tuple2<Integer, String> first, Tuple2<Integer, String> second) throws Exception {
if(second == null) {
return new Tuple3<Integer, String, String>(first.f0, first.f1, "-");
}
return new Tuple3<Integer, String, String>(first.f0, first.f1,second.f1);
}
}).print();
}右外连接：
data1.rightOuterJoin(data2).where(0).equalTo(0).with(new JoinFunction<Tuple2<Integer, String>, Tuple2<Integer, String>, Tuple3<Integer, String, String>>() {
@Override
public Tuple3<Integer, String, String> join(Tuple2<Integer, String> first, Tuple2<Integer, String> second) throws Exception {
if (first == null) {
return new Tuple3<Integer, String, String>(second.f0, "-", second.f1);
}
return new Tuple3<Integer, String, String>(first.f0, first.f1, second.f1);
}
}).print();全连接：
data1.fullOuterJoin(data2).where(0).equalTo(0).with(new JoinFunction<Tuple2<Integer, String>, Tuple2<Integer, String>, Tuple3<Integer, String, String>>() {
@Override
public Tuple3<Integer, String, String> join(Tuple2<Integer, String> first, Tuple2<Integer, String> second) throws Exception {
if (first == null) {
return new Tuple3<Integer, String, String>(second.f0, "-", second.f1);
} else if (second == null) {
return new Tuple3<Integer, String, String>(first.f0, first.f1, "-");
}
return new Tuple3<Integer, String, String>(first.f0, first.f1, second.f1);
}
}).print();笛卡尔积，左边与右边交叉处理
def crossFunction(env: ExecutionEnvironment): Unit = {
val info1 = List("乔峰", "慕容复")
val info2 = List(3,1,0)
val data1 = env.fromCollection(info1)
val data2 = env.fromCollection(info2)
data1.cross(data2).print()
}输出：
(乔峰,3)
(乔峰,1)
(乔峰,0)
(慕容复,3)
(慕容复,1)
(慕容复,0)public static void crossFunction(ExecutionEnvironment env) throws Exception {
List<String> info1 = new ArrayList<>();
info1.add("乔峰");
info1.add("慕容复");
List<String> info2 = new ArrayList<>();
info2.add("3");
info2.add("1");
info2.add("0");
DataSource<String> data1 = env.fromCollection(info1);
DataSource<String> data2 = env.fromCollection(info2);
data1.cross(data2).print();
}到此，关于“Apache下Flink transformation的用法”的学习就结束了，希望能够解决大家的疑惑。理论与实践的搭配能更好的帮助大家学习，快去试试吧！若想继续学习更多相关知识，请继续关注亿速云网站，小编会继续努力为大家带来更多实用的文章！
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原文链接：https://my.oschina.net/duanvincent/blog/3102483
