java List中如何筛选list中相同的值和筛选不同的值

本篇内容介绍了“java List中如何筛选list中相同的值和筛选不同的值”的有关知识，在实际案例的操作过程中，不少人都会遇到这样的困境，接下来就让小编带领大家学习一下如何处理这些情况吧！希望大家仔细阅读，能够学有所成！

public class People {
    private String id;
    private String somethingElse;

    public People() {
    }

    public People(String id, String somethingElse) {
        this.id = id;
        this.somethingElse = somethingElse;
    }

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getSomethingElse() {
        return somethingElse;
    }

    public void setSomethingElse(String somethingElse) {
        this.somethingElse = somethingElse;
    }

    @Override
    public String toString() {
        return "People{" +
                "id='" + id + '\'' +
                ", somethingElse='" + somethingElse + '\'' +
                '}';
    }
}

people实体类和student实体类
People类

student
public class Student {
    private String id;
    private String idCard;
    private String somethingElse;

    public Student() {
    }

    public Student(String id, String idCard, String somethingElse) {
        this.id = id;
        this.idCard = idCard;
        this.somethingElse = somethingElse;
    }

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getIdCard() {
        return idCard;
    }

    public void setIdCard(String idCard) {
        this.idCard = idCard;
    }

    public String getSomethingElse() {
        return somethingElse;
    }

    public void setSomethingElse(String somethingElse) {
        this.somethingElse = somethingElse;
    }

    @Override
    public String toString() {
        return "Student{" +
                "id='" + id + '\'' +
                ", idCard='" + idCard + '\'' +
                ", somethingElse='" + somethingElse + '\'' +
                '}';
    }
}

测试类

public static void main(String[] args) throws Exception{
//初始化数据
        List<Student> studentList = new ArrayList(){{
               add(new Student("1", "11", "111")) ;
               add(new Student("2", "22", "222"));
               add(new Student("3", "33", "333"));
        }};
        List<People> peopleList = new ArrayList(){
            {
                add(new People("11", "111"));
                add(new People("222", "222"));
                add(new People("33", "333"));
        }};
        //获取相同字段内容，转化为set
        Set<String> ids = peopleList
                .stream()
                .map(People::getId)
                .collect(Collectors.toSet());//过滤重复内容
        List<Student> result = studentList
                .stream()
                .filter(e -> ids.contains(e.getIdCard()))
                .collect(Collectors.toList());
        System.out.println(result);
         //获取相同字段内容，转化为set
        Set<String> ids = peopleList
                .stream()
                .map(People::getId)
                .collect(Collectors.toSet());//过滤重复内容
        List<Student> result = studentList
                .stream()
                .filter(e -> !ids.contains(e.getIdCard()))
                .collect(Collectors.toList());
        System.out.println(result);
}

“java List中如何筛选list中相同的值和筛选不同的值”的内容就介绍到这里了，感谢大家的阅读。如果想了解更多行业相关的知识可以关注亿速云网站，小编将为大家输出更多高质量的实用文章！