这篇文章将为大家详细讲解有关Python如何获取抖音关注列表封号账号,小编觉得挺实用的,因此分享给大家做个参考,希望大家阅读完这篇文章后可以有所收获。
最近抖音关注到达上限5000个了,所以就导致很多漂亮小姐姐没办法关注了,那么这里就通过python获取已经被封号的帐号取消关注就可以了
实现代码
import requests import json import time # 抖音创作者平台cookie header = {'Cookie': '你的COOKIE'} shijian = time.strftime("%Y-%m-%d %H:%M:%S", time.localtime()) sbdy = str(0) sl = 0 file = open("D:/test.txt", "a+",encoding='utf-8') file.write(shijian) yczh = 0 print(str(shijian)+"\n开始检测,请耐心等待...") while (sl < 5000): url = 'https://creator.douyin.com/aweme/v1/creator/relation/following/list/?aid=2906&app_name=aweme_creator_platform&device_platform=web&referer=https:%2F%2Fcreator.douyin.com%2Fcreator-micro%2Fhome&user_agent=Mozilla%2F5.0+(Windows+NT+10.0%3B+Win64%3B+x64)+AppleWebKit%2F537.36+(KHTML,+like+Gecko)+Chrome%2F90.0.4430.212+Safari%2F537.36&cookie_enabled=true&screen_width=1536&screen_height=864&browser_language=zh-CN&browser_platform=Win32&browser_name=Mozilla&browser_version=5.0+(Windows+NT+10.0%3B+Win64%3B+x64)+AppleWebKit%2F537.36+(KHTML,+like+Gecko)+Chrome%2F90.0.4430.212+Safari%2F537.36&browser_online=true&timezone_name=Asia%2FShanghai&_signature=_02B4Z6wo00901TSjMlwAAIDChFLelrWwFwk0pzbAAC2OgYeyEeDw.eiDhwpfH.4NSilIGJd.pSZ5de4SL4e-U2DQy-VLvH0NkfwTIp14WBZCgv63l6pLIkqBZMs9VRrdqIj3xOjfyY.2y6v8de&cursor='+sbdy+'&count=20' r = requests.get(url,headers=header) json_str = json.loads(r.text) if (int(json_str['status_code']) == int('0')): if ("user_info_list" in json_str): av = json_str['user_info_list'] for d in av: url = str(d['avatar']) if (url == "c16000003f97583dac4" or url == "b76600039bd12b4c09da"): print("用户名:"+d['nickname']+" 不正常") text = str('\n'+d['nickname']) file.write(text) sl+=1 yczh+=1 else: # print("用户名:"+d['nickname']+" 正常") sl+=1 sbdy = str(json_str['cursor']) else: print("检测完成,已检测账号"+str(sl)+"个,异常账号共计"+str(yczh)+"个") print("异常账号存储在: "+file.name) file.close() exit() else: if ("status_message" in json_str): print(json_str['status_message']+",已检测账号"+str(sl)+"个") print("等待3分钟继续执行") time.sleep(180) print("继续执行") else: print(json_str) print(sbdy) yn = input("是否重试,继续执行?[y/n]") if (yn == "n"): file.close() exit()
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